GREPS: find a white space between digit and a letter

I’m afraid I’m an idiot when it comes to grep. But you could do a simple search and replace.

1) In the find field, search for any digit + space + letter
2) Replace with the color red
3) Search for red space band
4) Replace with nothing, or designate a point size
5) Search for the color red
6) Replace with black (or the color the text is)

Of course, this is under the assumption it’s a one-color job, and the color red is not used. If it’s multi-color, then this probably wouldn’t work.

Hi Azamat,

Please try the following using GREP Find/Change:

Find what:
(\d)\x{0020}([\l\u])

Change to:
$1$2

Where “\x{0020” is the unicode value for a normal space. If you want any space than use “\s” instead of “\x{0020}” without quotes.

Let me know if it solves your problem.